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Comments (4)
johnlittlephysics said
at 9:01 am on Feb 6, 2013
Summary of features of s-t and v-t graphs
http://db.tt/9NFzmLWJ
johnlittlephysics said
at 10:39 pm on Feb 26, 2013
Driving a car safely: Thinking, braking and stopping distances
http://www.bbc.co.uk/schools/gcsebitesize/science/add_gateway_pre_2011/forces/motionrev3.shtml
Siew Kah Leng said
at 10:09 am on Sep 29, 2013
For WS1.6, Q5c(II), why does the velocity remain unchanged? Thank you!
johnlittlephysics said
at 5:34 pm on Sep 29, 2013
Q5(b) This can be answered by checking that the area under graph for A is equal to the area under graph for B.
The overtaking occurs when velocity of A = 2 x velocity of B. This is independent of the gradient of A (or acceleration of A).
Q5(c) (ii) When A has a larger acceleration, if you redraw the graph of A (larger gradient on v-t graph), the same conclusion is obtained:
i.e. the overtaking occurs when velocity of A = 2 x velocity of B. Hence same velocity.
Difference is a shorter time is taken, and a smaller distance is covered (area) when overtaking occurs.
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